The phosphorylation of fructose-6-phosphate is an endergonic reaction with a AG\deg of 16.3 kJ/mol. How do cells overcome this thermodynamic barrier for this reaction under standard conditions? A) This reaction will proceed to the right because the Keq is small.B) By uncoupling the reaction to the hydrolysis of ATP, the reaction can be driven forward.The enzyme that catalyzes this reaction couples it with the hydrolysis of ATFC)to ADP and inorganic phosphate, resulting in an overall AG\deg -of -14.2 kJ/mol.The enzyme that catalyzes this reaction couples it with the condensation ofDADP and inorganic phosphate, resulting in an overall AG\deg of -46.8 kJ/mol. E) This reaction will proceed to the right because the Keq is negative.