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richard hernandez

richard h.

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(1 point) Give the growth factor $b$, the starting value $a$, the growth rate $r$, and the value of $k$ when $Q$ is written in the form $Q = a e^{kt}$. If there is exponential decay, then your growth rate should be negative. For help entering logarithms, see help (logarithms) $Q = 220 \cdot (1.898)^t$ has: $b = \text{_____}$ help (numbers) $a = \text{_____}$ help (numbers) $r = \text{_____}$ help (numbers) $k = \text{_____}$ help (numbers)

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In the light reactions of photosynthesis, sunlight boosts electrons into a higher energy state, and those electrons are later used in making sugars. Where do chloroplasts get more electrons to replace those boosted by sunlight? O NADPH O CO? O NADH O H?O

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The scientific name of an organism comes from its genus and domain genus and species kingdom and species kingdom and domain

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Identify 4 instructional practices or strategies for providing evidence-based reading instruction.

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For the pair of compounds, \( \mathrm{Cs}_{2} \mathrm{O} \) and \( \mathrm{H}_{2} \mathrm{O} \), classify the bonding as ionic or covalent and explain your choice. Select the single best answer for each part. Part 1 of 2 \( \mathrm{Cs}_{2} \mathrm{O} \) is ionic since both atoms are metals. \( \mathrm{Cs}_{2} \mathrm{O} \) is ionic since one atom is metal and the other is nonmetal. \( \mathrm{Cs}_{2} \mathrm{O} \) is covalent since one atom is metal and the other is nonmetal. \( \mathrm{Cs}_{2} \mathrm{O} \) is covalent since both atoms are nonmetals. \( \mathrm{Cs}_{2} \mathrm{O} \) is ionic since both atoms are nonmetals. \( \mathrm{Cs}_{2} \mathrm{O} \) is covalent since both atoms are metals. Part 2 of 2 \( \mathrm{H}_{2} \mathrm{O} \) is ionic since both atoms are nonmetals. \( \mathrm{H}_{2} \mathrm{O} \) is covalent since both atoms are metals. \( \mathrm{H}_{2} \mathrm{O} \) is covalent since one atom is metal and the other is nonmetal. \( \mathrm{H}_{2} \mathrm{O} \) is ionic since both atoms are metals. \( \mathrm{H}_{2} \mathrm{O} \) is covalent since both atoms are nonmetals. \( \mathrm{H}_{2} \mathrm{O} \) is ionic since one atom is metal and the other is nonmetal.

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what is the maximum number the HHI can take? a. 100 b. 1000 c. 10000 d. 100000 and e. 1000000

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1) Refer to section 1 and 1a in the notes Let $h(x) = 2x^2 - 3x + 7$. Compute and simplify • Find h(-3) • Find h(2a-5)

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(e): Probability that a student who has an American Express Card (event C) also have a Visa card or a MasterCard ( Acup B because of "or") is P(Acup B|C)=^((1))(P[(Acup B)cap C])/(P(C))=^((2))(P[(Acap C)cup (Bcap C)])/(P(C)) =^((3))(P(Acap C)+P(Bcap C)-P[(Acap C)cap (Bcap C)])/(P(C)) =(P(Acap C)+P(Bcap C)-P(Acap Bcap C))/(P(C)) =^((4))(0.15+0.1-0.08)/(0.2) =0.85, (1) : here we use definition of conditional probability given below, where Acap B is a single event, (2) : this stands for any three event A,B and C, (3) : we use the proposition given below where events Acap B and Bcap C are the single events (first one is A_(1)=Acap B from the definition, second one is B_(1)=Bcap C from the definition), (4) : the probabilities are given in the exercise. Proposition: For every two events A_(1) and B_(1) P(A_(1)cup B_(1))=P(A_(1))+P(B_(1))-P(A_(1)cap B_(1)). Conditional probability of A given that the event B has occurred, for which P(B)>0, is P(A|B)=(P(Acap B))/(P(B)) for any two event A and B. Suppose that an individual is randomly selected from the population, and define events by type A selected ***I NEED HELP WITH E.) I DONT UNDERSTAND THE SOLUTION AND HOW THE FORMULA WAS DERIVIED*** (e): Probability that a student who has an American Express Card (event C) also have a Visa card o a MasterCard ( A U B because of or) is 47, Return to the credit card scenario of Exercise 12 (Sec- tion 2.2), and let C be the event that the selected student has an American Express card. In addition to P(A) = .6, P(B) = .4, and P(A B) = .3, suppose that P(C) = .2, P(A C) = .15, P(B C) = .1, and P(A N B N C) = .08. a. What is the probability that the selected student has at least one of the three types of cards? h. What is the probability that the selected student has both a Visa card and a MasterCard but not an American Express card? e. Calculate and interpret P(|A) and also P(A|). P(C P(C) gP(4nC)+P(BnC)-P[(AnC)n(BnC) P(C) P(AnC)+P(BnC)P(AnBnC) P(C) 0.15 + 0.1 0.08 0.2 0.85, Suppose that an individual is randomly selected from the population, and define events byA = (type A selected,=type B selected),andC=(ethnic group 3 selected}. a. Calculate P(A), P(C), and P(A C). b, Calculate both P(A|C) and P(C|A), and explain in context what each of these probabilities represents. (1) : here we use definition of conditional probability given below, where A B is a single event, (2) : this stands for any three event A,B and C, (3) : we use the proposition given below where events A B and B C are the single events (first one is A = A .B from the definition, second one is B = B C from the definition), d.If we learn that the selected student has an American Express card, what is the probability that she or he also has both a Visa card and a MasterCard? e.Given that the selected student has an American Express e d one of the other two types of cards? (4) : the probabilities are given in the exercise Proposition: For every two events A and B P(A U B) = P(A) + P(B) P(A B). Conditional probability of A given that the event B has occurred, for which P(B) > 0, is P(AB) P(A|B)= P(B) for any two event A and B.

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The personal fable refers to an adolescent's imagining that he or she is: Question 16 options: the center of attention wherever he or she goes. playing a role rather than living a real life. much smarter and wiser than his or her parents. destined to live a heroic life.

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Parallel line equation: y = -0.3x + b Perpendicular line equation: y = 3.33x + b

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