Find the velocity \(\vec{v}(t)\) and the speed \(\|\vec{v}(t)\|\) of a particle with position
\(x = 4\), \(y = t^2 - 8t + 16\), \(z = 4t^3 - 24t^2\).
\(\vec{v}(t) = \langle 0, 2t - 8, 12t^2 - 48t \rangle\)
speed \(\|\vec{v}(t)\|\) =
Find any times at which the particle stops.
t =
(Give your answer as a time or list of times, comma separated.)