Question

1. (44 points) CHAPTER 12. A 9.0 m uniform beam is hinged to a vertical wall and held horizontally by a 5.0 m cable attached to the wall 4.0 m above the hinge, as shown below. The metal of the cable has test strength of 1.00 KN (kilo-Newton), which is the maximum tension magnitude T the cable can support. That means the cable will break if T is greater than this value. (a) (4 points) What is the angel ?? (b) (4 points) What is the distance along the bean between the hinge and where the cable is attached to the beam? (c) (32 points) What is the largest beam mass m (corresponding to the test strength) the cable can support with the given configuration shown? Hint: Set the next torques to be zero about the axis at the intersection between the beam and the wall at the hinge. THE TORQUES THAT ADD TO ZERO ARE DUE TO THE TENSION AND THE DOWNWARD WEIGHT OF THE BEAM. THEN SOLVE FOR THE MASS m. Remember. The magnitude of the weight is mg. (d) (4 points) Find the horizontal and vertical components of the force the hinge exerts on the beam,

          1. (44 points) CHAPTER 12. A 9.0 m uniform beam is hinged to a vertical wall and held horizontally by a 5.0 m cable attached to the wall 4.0 m above the hinge, as shown below. The metal of the cable has test strength of 1.00 KN (kilo-Newton), which is the maximum tension magnitude T the cable can support. That means the cable will break if T is greater than this value.

(a) (4 points) What is the angel ??

(b) (4 points) What is the distance along the bean between the hinge and where the cable is attached to the beam?

(c) (32 points) What is the largest beam mass m (corresponding to the test strength) the cable can support with the given configuration shown? Hint: Set the next torques to be zero about the axis at the intersection between the beam and the wall at the hinge. THE TORQUES THAT ADD TO ZERO ARE DUE TO THE TENSION AND THE DOWNWARD WEIGHT OF THE BEAM. THEN SOLVE FOR THE MASS m. Remember. The magnitude of the weight is mg.

(d) (4 points) Find the horizontal and vertical components of the force the hinge exerts on the beam,

1. (44 points) CHAPTER 12. A 9.0 m uniform beam is hinged to a vertical wall and held horizontally by a 5.0 m cable attached to the wall 4.0 m above the hinge, as shown below. The metal of the cable has test strength of 1.00 KN (kilo-Newton), which is the maximum tension magnitude T the cable can support. That means the cable will break if T is greater than this value.

(a) (4 points) What is the angel ??

(b) (4 points) What is the distance along the bean between the hinge and where the cable is attached to the beam?

(c) (32 points) What is the largest beam mass m (corresponding to the test strength) the cable can support with the given configuration shown? Hint: Set the next torques to be zero about the axis at the intersection between the beam and the wall at the hinge. THE TORQUES THAT ADD TO ZERO ARE DUE TO THE TENSION AND THE DOWNWARD WEIGHT OF THE BEAM. THEN SOLVE FOR THE MASS m. Remember. The magnitude of the weight is mg.

(d) (4 points) Find the horizontal and vertical components of the force the hinge exerts on the beam,

Added by Gary B.

Question

Please give Ace some feedback