00:01
In this question, we are asked to find the area of the region enclosed by the given curves.
00:05
First, let's make a sketch of the region.
00:18
So, y equals x squared is a regular parabola.
00:21
It goes through the origin, the points 1 -1, negative 1 -1.
00:28
At x equals 2, it's 4.
00:35
At x equals negative 2, it's also 4.
00:40
And when x equals to 3, it equals to 9.
00:43
And x at x equals negative 3 it's also 9 so here is the is the graph of y equals to x squared now let's sketch the graph of y equals 3x when x equals 0 when x equals 1 y equals 3 when x equals 2 y equals 6 and when x equals 3 y equals to 9 so this is a graph of y equals to 3 x and you can see clearly the region enclosed by the given curves.
01:46
To find the area of the region, we need to calculate the integral from a to b of f minus g dx, where f is the upper boundary of the region and g is a lower boundary of the region.
02:03
In our case, the upper boundary, we can see the upper boundary from the picture.
02:11
From the top, the region bounded by 3x...