Question

1. Find the value of \( x \) which satisfies the equation: \[ 16 x^{2}=8^{(4 x-3)} \] 2. By letting \( P=4^{-y} \) in the equation, Find the value of \( y \). \[ 4^{(-2 y+1)}-3 \times 4^{-y}-10=0 \]

          1. Find the value of \( x \) which satisfies the equation:
\[
16 x^{2}=8^{(4 x-3)}
\]
2. By letting \( P=4^{-y} \) in the equation, Find the value of \( y \).
\[
4^{(-2 y+1)}-3 \times 4^{-y}-10=0
\]

1. Find the value of x which satisfies the equation:

16 x^2=8^(4 x-3)

2. By letting P=4^-y in the equation, Find the value of y.

4^(-2 y+1)-3 × 4^-y-10=0

Added by Joel W.

Intermediate Algebra

Jerome E. Kaufmann, Karen L. Schwitters 10th Edition

Chapter 11

Thanks for your feedback!

1. Find the value of \( x \) which satisfies the equation: \[ 16 x^{2}=8^{(4 x-3)} \] 2. By letting \( P=4^{-y} \) in the equation, Find the value of \( y \). \[ 4^{(-2 y+1)}-3 \times 4^{-y}-10=0 \]