Question

(1 point) Evaluate the limit $ \lim_{x \to 1} \frac{x^2 - 4x + 3}{x^2 - 1} $ Enter inf for $\infty$, -inf for $-\infty$, and DNE if the limit does not exist. Limit =

          (1 point) Evaluate the limit

\( \lim_{x \to 1} \frac{x^2 - 4x + 3}{x^2 - 1} \)

Enter inf for $\infty$, -inf for $-\infty$, and DNE if the limit does not exist.
Limit =

(1 point) Evaluate the limit

limx → 1(x^2 - 4x + 3)/(x^2 - 1)

Enter inf for ∞, -inf for -∞, and DNE if the limit does not exist.
Limit =

Added by Virginia C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

03/23/2023

Step 1

Step 1: To evaluate the limit \lim_(x->1)(x^(2)-4x+3)/(x^(2)-1), we can first factor the numerator and denominator. Show more…

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(1 point) Evaluate the limit lim_(x->1)(x^(2)-4x+3)/(x^(2)-1) Enter inf for infty , -inf for -infty , and DNE if the limit does not exist. Limit = (1 point) Evaluate the limit 22 4x+3 lim x1 x2-1 Enter inf for ,-inf for -,and DNE if the limit does not exist. Limit =