Suppose h is a function such that h(1) = -8, h'(1) = 4, h”(1) = 8, h(6) = 4, h'(6) = -11, h”(6)

Name: Suppose h is a function such that h(1) = -8, h'(1) = 4, h”(1) = 8, h(6) = 4, h'(6) = -11, h”(6) = 18, and h” is continuous everywhere. Then ∫1^6 h”(u) du =
Uploaded: 2022-07-19T17:20:54-08:00
Duration: 2 min 40 s
Channel: Adi S
Description: Suppose h is a function such that h(1) = -8, h'(1) = 4, h”(1) = 8, h(6) = 4, h'(6) = -11, h”(6) = 18, and h” is continuous everywhere. Then ∫1^6 h”(u) du =

To start, we need to find the derivative of h with respect to u. This can be done by taking the

Question

Suppose \(h\) is a function such that \(h(1) = -8, h'(1) = 4, h''(1) = 8, h(6) = 4, h'(6) = -11, h''(6) = 18,\) and \(h''\) is continuous everywhere. Then \(\int_1^6 h''(u) du = \)

          Suppose \(h\) is a function such that \(h(1) = -8, h'(1) = 4, h''(1) = 8, h(6) = 4, h'(6) = -11, h''(6) = 18,\) and \(h''\) is continuous everywhere. Then \(\int_1^6 h''(u) du = \)