Question

(1 point) Solve the matrix equations Ax = b, where \begin{align} \text{a) } A = \begin{bmatrix} 2 & 6 \\ -5 & -2 \end{bmatrix}, \quad x = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} \text{ and } b = \begin{bmatrix} 10 \\ 1 \end{bmatrix} . \end{align} The solution is: $x_1 = $ $x_2 = $ \begin{align} \text{b) } A = \begin{bmatrix} 2 & 6 \\ -5 & -2 \end{bmatrix}, \quad x = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} \text{ and } b = \begin{bmatrix} -16 \\ 27 \end{bmatrix} . \end{align} The solution is: $x_1 = $ $x_2 = $ \begin{align} \text{c) } A = \begin{bmatrix} 2 & 6 \\ -5 & -2 \end{bmatrix}, \quad x = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} \text{ and } b = \begin{bmatrix} -18 \\ 6 \end{bmatrix} . \end{align} The solution is: $x_1 = $ $x_2 = $

          (1 point) Solve the matrix equations Ax = b, where
\begin{align*} \text{a) } A = \begin{bmatrix} 2 & 6 \\ -5 & -2 \end{bmatrix}, \quad x = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} \text{ and } b = \begin{bmatrix} 10 \\ 1 \end{bmatrix} . \end{align*} The solution is:
$x_1 = $ 
$x_2 = $
\begin{align*} \text{b) } A = \begin{bmatrix} 2 & 6 \\ -5 & -2 \end{bmatrix}, \quad x = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} \text{ and } b = \begin{bmatrix} -16 \\ 27 \end{bmatrix} . \end{align*} The solution is:
$x_1 = $ 
$x_2 = $
\begin{align*} \text{c) } A = \begin{bmatrix} 2 & 6 \\ -5 & -2 \end{bmatrix}, \quad x = \begin{bmatrix} x_1 \\ x_2 \end{bmatrix} \text{ and } b = \begin{bmatrix} -18 \\ 6 \end{bmatrix} . \end{align*} The solution is:
$x_1 = $ 
$x_2 = $

(1 point) Solve the matrix equations Ax = b, where

a) A =
< b m a t r i x >
, x =
< b m a t r i x >
and b =
< b m a t r i x >
.
The solution is:
x1 =
x2 =

b) A =
< b m a t r i x >
, x =
< b m a t r i x >
and b =
< b m a t r i x >
.
The solution is:
x1 =
x2 =

c) A =
< b m a t r i x >
, x =
< b m a t r i x >
and b =
< b m a t r i x >
.
The solution is:
x1 =
x2 =

Added by Joshua J.

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