Question

What is the Laplace transform of the solution of the initial value problem dx/dt + 3x = sin(t), x(0) = 1? a. It is not possible to find the Laplace transform b. (s^2 + 2) / ((s + 3)(s^2 + 1)) c. 1/((s + 3)(s^2 + 1)) d. s(s^2 + 2)/((s^2 + 1)(s + 3))

Name: 1 what is the laplace transform of the solution of the initial value problem dxdt 3x sint x0 1 a it is not possible to find the laplace transform bs2 2 s 3s2 1 c 1s 3s2 1 d ss2 2s2 1s 3 2 wh 10139
Uploaded: 2022-05-31T09:40:48-08:00
Duration: 7 min 41 s
Channel: Adi S
Description: 1 what is the laplace transform of the solution of the initial value problem dxdt 3x sint x0 1 a it is not possible to find the laplace transform bs2 2 s 3s2 1 c 1s 3s2 1 d ss2 2s2 1s 3 2 wh 10139

          What is the Laplace transform of the solution of the initial value problem dx/dt + 3x = sin(t), x(0) = 1?
a. It is not possible to find the Laplace transform
b. (s^2 + 2) / ((s + 3)(s^2 + 1))
c. 1/((s + 3)(s^2 + 1))
d. s(s^2 + 2)/((s^2 + 1)(s + 3))

Added by Jasmine H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

05/31/2022

Step 1

Step 1:** The Laplace transform of the differential equation \( \frac{dx}{dt} + 3x = \sin(t) \) with initial condition \( x(0) = 1 \) is given by: \[ X(s) = \frac{s^2 + 2}{(s + 3)(s^2 + 1)} \] ** Show more…

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What is the Laplace transform of the solution of the initial value problem dx/dt + 3x = sin(t), x(0) = 1? a. It is not possible to find the Laplace transform b. (s^2 + 2) / ((s + 3)(s^2 + 1)) c. 1/((s + 3)(s^2 + 1)) d. s(s^2 + 2)/((s^2 + 1)(s + 3))