1- What is the length of the parametric curve given by x=4t^ 2 -2t\\ y= 16/3 * t ^ (3/2) in the interval 0 <= t <= 1? a)3 b)6 c)10 d)15 e) None
Added by Emre T.
Step 1
dx/dt = d(4t^2 - 2t)/dt = 8t - 2 dy/dt = d(16/3 * t^(3/2))/dt = 16/3 * (3/2) * t^(1/2) = 8t^(1/2) Show more…
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