Question

The dose-response for a specific drug is $f(x) = \frac{100x^2}{x^2 + 0.34}$, where $f(x)$ is the percent of relief obtained from a dose of $x$ grams of a drug, where $0 \le x \le 1.5$. For doses of 0.2 grams and 0.8 grams, calculate $f(x)$ and $f'(x)$ f(0.2) = f'(0.2) = f(0.8) = f'(0.8) =

          The dose-response for a specific drug is $f(x) = \frac{100x^2}{x^2 + 0.34}$, where $f(x)$ is the percent of relief obtained from a dose of $x$ grams of a drug, where $0 \le x \le 1.5$.
For doses of 0.2 grams and 0.8 grams, calculate $f(x)$ and $f'(x)$ 
f(0.2) = 

f'(0.2) = 
f(0.8) = 
f'(0.8) =
        
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The dose-response for a specific drug is f(x) = (100x^2)/(x^2 + 0.34), where f(x) is the percent of relief obtained from a dose of x grams of a drug, where 0 ≤ x ≤ 1.5.
For doses of 0.2 grams and 0.8 grams, calculate f(x) and f'(x) 
f(0.2) = 

f'(0.2) = 
f(0.8) = 
f'(0.8) =

Added by Mitchell B.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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The dose-response for a specific drug is obtained from a dose of grams of a drug, where f = 01.5. For doses of 0.2 grams and 0.8 grams, calculate f and f'. f(0.2) = f'(0.2) = f(0.8) - f(0.8) =
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Transcript

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00:01 So this is the given function f of x.
00:03 Now if we calculate f dash of x, we get x squared plus 0 .38 into 200x.
00:13 This derivative minus 100x square into 2x divided by x squared plus 0 .6 divided by x squared plus 0 .38 whole square...
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