13 Global Extrema: Problem 2 (8 points) Consider the...

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00:01 Okay, for this problem, we are supposed to graph this function f of x equals 2 minus 2x squared within the window from negative 3 to 2 on my x -axis.

00:14 So, we could graph it with our calculator, but i'm going to make a table.

00:26 Alright, i'm going to start at negative 3 and go to positive 2.

00:32 Alright, when i put in for x a negative 3, i get 2 minus 2 times negative 3 squared, which is 9.

00:42 2 minus 18 is negative 16.

00:46 When i put a negative 2 in, i get 2 minus 2 times negative 2 squared is 4, and 2 minus 8 is negative 6, and i would get the same thing if i put in a positive 2, because you see when you square it, you're going to get the same thing.

01:06 When i put a negative 1 in, 2 minus 2 times negative 1 squared is 1, and 2 minus 2 is 0, and i would get that for 1 also.

01:19 And for 0, 2 minus 2 times 0 is 2.

01:25 So, i'm going to graph this.

01:41 Alright, that's negative 6, and i'm just going to come down here a ways and put negative 16.

01:46 Alright, so at negative 3, it's negative 16.

01:56 At negative 2, it's negative 6, and it's negative 6 at positive 2 as well.

02:07 At negative 1 and at positive 1, it's at 0, and at 0, it's at 2.

02:19 So, you know, these graphs go on and on forever, but i'm going to actually stop it within this window...

Question

13 Global Extrema: Problem 2 (8 points) Consider the function $r(t) = t - 2\ln(t)$ on $\frac{1}{2} \le t \le 8$. Absolute Maximum value at $t = $ Absolute Minimum value at $t = $

Question

13 Global Extrema: Problem 2 (8 points) Consider the function $r(t) = t - 2\ln(t)$ on $\frac{1}{2} \le t \le 8$. Absolute Maximum value at $t = $ Absolute Minimum value at $t = $

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