It is a triple integral in spherical coordinates, which can be written as:
$$\int_{0}^{2\pi}\int_{0}^{\frac{\pi}{2}}\int_{0}^{6} \rho^2 \sin{\phi} \, d\rho \, d\phi \, d\theta$$
Now, let's sketch the solid. The limits of integration for $\rho$ are from 0 to 6,
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