00:01
Problem number 18, to approximate the root of the given function, a root r of the given function, f and the initial approximation x note, we use the newton's method.
00:15
The formula that we use for this is xn plus 1, which is equal to xn minus f of xn over f dash of xn.
00:28
In our case, f of x equals x multiplied n of x plus 1, minus 1, and f of x, and f, f, dash of x equals len of x plus 1 plus x over x plus 1.
00:47
And finally x node equals 1 .7.
00:52
We should stop calculating approximations when two successive approximations agree to 5 digits to the right of the decimal point after rounding.
01:03
Now let's draw the table for our iterations.
01:08
Xn, f of xn, f, f, of x n and x n minus f of x n over f dash of x n okay now let's choose a thinner thickness for our pen okay the beginning iteration zero x note equals 1 .7 .68853 on point 6 -2288 -8 -8 1 .2 -8 -1 .2757 eritation number 1 .1 .27 .574 .04905.
02:09
1 .38289 .1 .2277...