00:01
For this question, we are going to find all the rational and irrational zeros of the given polynomial function using all of the tools that we know.
00:10
Let's start with the rational zeros theorem.
00:13
Our possible solutions are going to be positive or negative factors of six over factors of two.
00:32
So our possible things we're going to try are positive or negative 1 over 1, 2 over 1, 3 over 1, 6 over 1, 1 over 2, 2 over 2, which is 1, 3 over 2, and 6 over 2, which is 3.
00:55
Because all of the signs in our polynomial function are positive, one of our zeros must be negative.
01:03
So i'm going to start with one of my negatives.
01:07
And i've done some preliminary work ahead of time and know that negative 3 is one of the zeros that will work.
01:23
Bring down the 2.
01:25
Multiply.
01:27
Combine.
01:28
Multiply, combine, multiply, combine, multiply, combine, multiply, and we have a zero.
01:40
All right.
01:41
Now we have a cubic function that we need to try and find another value for.
01:57
But notice the ending number, the constant term, is a two.
02:04
That means we will no longer have to try positive or negative 3, positive or negative 6, positive or negative 3 halves.
02:13
We will try negative 1 1⁄2...