00:01
In this problem, we have 10 printers out of which 6 are laser printers and 4 are inkjet printers.
00:12
Now, for party of the problem, we want to select 2 laser and 1 inkjet.
00:22
So, the probability for this will be for selecting 2 laser, we have 6 c2 options and for selecting 1 inkjet, we have 4 c1 options and the total possible options of choosing 3 out of 10 is 10 c3.
00:36
So, this is the probability, this is nothing but 6 into 5 into 4 by 2 into this is 10 into 9 into 8 and then 6 goes here.
00:53
So, this becomes 6 5 xi is 30.
00:58
So, this and this cancels, this stays as 3, this is 1 xi, this is 3 xi, this is 1 xi, this is 2 xi, this and this also cancels.
01:08
So, we simply get 4 over 8, which is 1 over 2.
01:23
Next, for part b, we want to have all 3 of the same models...