2. One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates "artificial gravity" at the outside rim of the station. If the radius of the space station is 500 [m], what is the required period of rotation of the space station for the "artificial gravity" acceleration to be 9.80 [mĀ·s?Ā²]? (A) 24.0 [s] (B) 225 [s] (C) 146 [s] (D) 53.1 [s] (E) 44.9 [s]
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80 m/sĀ² at the rim of the space station. We can use the formula for centripetal acceleration: a = ĻĀ² * r where a is the artificial gravity acceleration (9.80 m/sĀ²), Ļ is the angular velocity, and r is the radius of the space station (500 m). Now, we can solve Show moreā¦
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One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates "artificial gravity" at the outside rim of the station. (a) If the diameter of the space station is $890 \mathrm{~m}$, how many revolutions per minute are needed for the "artificial gravity" acceleration to be $9.80 \mathrm{~m} / \mathrm{s}^{2} ?(\mathrm{~b})$ If the space station is a waiting area for travelers going to Mars, it might be desirable to simulate the acceleration due to gravity on the Martian surface $\left(3.70 \mathrm{~m} / \mathrm{s}^{2}\right) .$ How many revolutions per minute are needed in this case?
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One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates "artificial gravity" at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the "artificial gravity" acceleration to be 9.80 m/s$^2$? (b) If the space station is a waiting area for travelers going to Mars, it might be desirable to simulate the acceleration due to gravity on the Martian surface (3.70 m/s$^2$). How many revolutions per minute are needed in this case?
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