00 nC, Q2 = +2.00 nC, and the distance between them is 0.20 m, we have:
\( F_{12} = \frac{{9 \times 10^9 \cdot 9 \times 10^{-9} \cdot 2 \times 10^{-9}}}{{(0.20)^2}} \)
\( F_{12} = \frac{{162 \times 10^{-18}}}{{0.04}} \)
\( F_{12} = 4.05 \times 10^{-6} \, N \)
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