y'' + 2y' = u(t - 5), y(0) = 1, y'(0) = 1. Taking Laplace transforms gives $s^2 Y(s) - s - 1 + 2(sY(s) - 1) = frac{e^{-5s}}{s} implies Y(s) = frac{e^{-5s}}{s(s^2 + 2s)} + frac{s + 3}{s^2 + 2s}$
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Start with the given differential equation: 2y = t - 5. Show more…
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