3. [0 / 1 Points] Evaluate the integral. $$ \int_{0}^{2} \left( \frac{4}{5}t^3 - \frac{3}{4}t^2 + \frac{2}{5}t \right) dt $$ Need Help? Read It SUBMIT ANSWER 4. [0 / 1 Points]
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The integral to be evaluated is: $$ \int_{0}^{2} \left( \frac{4}{5}t^3 - \frac{3}{4}t^2 + \frac{2}{5}t \right) dt $$ Show more…
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$19-38$ Evaluate the integral. $$\int_{0}^{2}\left(\frac{4}{5} t^{3}-\frac{3}{4} t^{2}+\frac{2}{5} t\right) d t$$
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Evaluate the integral. $ \displaystyle \int^2_0 \biggl(\frac{4}{5}t^3 - \frac{3}{4}t^2 + \frac{2}{5}t \biggr) \,dt $
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