00:01
Hello students, in this question we have been given a cross of various alleles.
00:06
So first let us assign the alleles for each gene.
00:09
So black body, that is b and brown body, b+.
00:19
We have waxy wings, which is wx and non -waxy is wx+.
00:31
Then we have cinnabar eyes, cn and then we have red eyes, which is cn+.
00:44
The wild type female is heterozygous for all three genes.
00:48
So her genotype is bb +, wx +, cn+.
01:00
The homozygous male has a black body, waxy wing.
01:06
Waxy wings and cinnabar eyes, so his genotype is bb, wx, wx, cn, cn.
01:14
Now let's analyze the progeny.
01:17
So we have 381 cinnabar, 379 black waxy and 72 waxy cinnabar...