Question

3. (2 points) Calculate a modular inverse matrix A (a) Inverse of $A = \begin{bmatrix} 5 & 3\\ 9 & 6 \end{bmatrix}$ modulo 4 (b) Inverse of $A = \begin{bmatrix} 8 & -3\\ 2 & 1 \end{bmatrix}$ modulo 9 (c) $A = \begin{bmatrix} 2 & 4 & 0\\ 3 & 3 & -5\\ -1 & 2 & 6 \end{bmatrix}$ modulo 13 (d) $A = \begin{bmatrix} 2 & 5 & 11\\ -14 & 1 & -9\\ 13 & -17 & 3 \end{bmatrix}$ modulo 23

          3. (2 points) Calculate a modular inverse matrix A
(a) Inverse of $A = \begin{bmatrix} 5 & 3\\ 9 & 6 \end{bmatrix}$ modulo 4
(b) Inverse of $A = \begin{bmatrix} 8 & -3\\ 2 & 1 \end{bmatrix}$ modulo 9
(c) $A = \begin{bmatrix} 2 & 4 & 0\\ 3 & 3 & -5\\ -1 & 2 & 6 \end{bmatrix}$ modulo 13
(d) $A = \begin{bmatrix} 2 & 5 & 11\\ -14 & 1 & -9\\ 13 & -17 & 3 \end{bmatrix}$ modulo 23

3. (2 points) Calculate a modular inverse matrix A
(a) Inverse of A =
< b m a t r i x > modulo 4
(b) Inverse of A =
< b m a t r i x > modulo 9
(c) A =
< b m a t r i x > modulo 13
(d) A =
< b m a t r i x > modulo 23

Added by Amy B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

02/25/2023

Step 1

For matrix A = [4 6 6; 2 4 3; 3 1 2], the determinant can be calculated as follows: det(A) = 4(4*2 - 3*1) - 6(2*2 - 3*3) + 6(2*1 - 4*3) = 4(8 - 3) - 6(4 - 9) + 6(2 - 12) = 4(5) - 6(-5) + 6(-10) = 20 + 30 - 60 = -10 Show more…

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3. (2 points) Calculate a modular inverse matrix A (a) Inverse of A = modulo 4 6 6 2 4 3 3 1 2 0] 5 modulo 13 6] (c)A (b) Inverse of A = 2 modulo 9 2 5 11] 14 1 9 modulo 23 13 17 3] (d) A