00:01
In the question they given two figures.
00:04
Here we have to find out express each of the signals by a single expression valid for all t.
00:12
Here we have to take this is slope 1.
00:15
This is slope 2.
00:17
In figure a we have to write slope of 1 equal to plus 4 by 1 that equal to 4.
00:32
N slope of 2 equal to minus 4 divided by 2 equal to minus 2.
00:41
Here got cancelled 2 1's 2 2s.
00:45
Therefore x 1 of t equal to 4r t plus 1 minus 4r t minus 0 minus 2r t minus 0 plus 2 r t minus 0 plus 2 r t minus 0 plus 2 r 2 r 2 r 2 0 plus 2 r.
01:03
T minus 2 we can simplify this equation equal to 4 r t plus 1 minus 4 r of t minus 2 r of t minus 2 r of t minus 2 r of 2 here x of x 1 of t value is x 1 of t equal to 4 r t plus 1 t plus 1 minus 4 r t plus 1 minus 4 r of t minus two r of t is minus six r of t plus r of t plus two or t minus two it is x1 value here r of t equal to t of four of t now we can see the figure b slope of one is we have to write then we have to write in final equation also so first we have to write slope equal to plus 4 by 2 that equal to plus 2.
02:26
Therefore x2 of t equal to t square 4 of t minus 2 whole square 4 t minus 2 minus 8 4 t minus 2 plus 2 r of t minus 2 minus 2 minus 2 or t minus 4.
02:51
Here in this question they can find express each of the signals by a single expression valid for all t.
03:01
Here we can write that single expressions...
