00:01
So here we have to determine the transfer function that is x2s which is divided by fs for the system which we have shown here.
00:08
So here the force that is ft is acting where the mass m1 is given that is one kilogram which is connected again with the mass m2 which is again one kilogram.
00:20
So from here the force x1 is given and from here that is x2 is given.
00:26
This is the surface from here where we are given the value of k that is equals to one newton per meter.
00:32
So this is the system is given we have to find out the value of x2s divided by fs.
00:37
So here this is the value if we can draw the node diagram for the given.
00:43
So this is what we are considering.
00:46
This is m1 and this from here k is connected that is m2.
00:53
So this is the term which we are given here k this is x2 of t this is x1 of t.
01:00
So here at node 1 we are considering the equation will be m1 d of x1 square divided by dt square plus k multiplied by the x1 minus x2 that is equals to f of t.
01:15
So this from here is equals d of x1 to its whole square divided by dt to its whole square plus x1 minus x2 which is equals to f of t...