00:02
In this problem for the circuit shown use the superposition method to find ir2 right so here is the superposition theorem we will apply here right so basically to find the to find the superposition theorem the superposition theorem says that you have to find the current right taking only one independent voltage source right and short -circuiting all other voltage voltage sources and independent current source we will just short the independent voltage source and we will just open circuit the independent current sources remember this this is going to help you a lot in solving the superposition theorem so now if you talk about i are 2 right so first of all we will do we will take vs 1 activated right so let us make the diagram so first step 1 is this only we will just take only vs 1 here while we will just short circuit other voltage sources so only second voltage sources vs 2 so we will just short circuit it we will be getting the diagram like this so now this is the diagram we have got now this is this is i are 2 right so now this will be equal to so let us put the values as well so here it is 26 k this is 68k this is 12k and this is 47k and this is 47k and this one is 56 right so when you resolve the circuit you will be getting after solving you will be getting a circuit like this this is 6 volts 6 volts isn't it? vs 1 is 6 volts already given this or values are given to us so now this becomes one resistor here and we have one resistor here then we have another resistor here so we will be getting this is 27k while this is i and this is i are 2 right so now let me write a small i only so it must not confuse you so here i are two dash because we are taking only one independent source so here it becomes 56 k and here we have 77 .55k here isn't it so therefore you can say that r dash equals to 68 plus 68 plus what 68, right, 68 and we can say that 12 and already i have told that 68 which is 12 panel to 47.
04:31
I have solved it in this way.
04:34
So this becomes equals to when you solve this you will be getting 77 .5k here.
04:40
So this is r dash.
04:42
So this is what we have got this value as equals to r dash.
04:46
Right.
04:48
So i'm just writing this off, right? but there's no need because you can just easily solve it by your own.
04:59
Simply just solving in your own mind itself, right? so it is so easy calculation.
05:06
So now here when you solve this, you will be getting i equals to v by total r.
05:14
So what is total r? this is 27 plus 56 parallel to 70.
05:20
27 .5 which is equals to 6x27 plus 4342 .8 divided by 133 .55.
05:37
So this will be giving us the value i equals to 6 by 59 .518.
05:46
So now this is equal to 100 .8 microamperes...