00:01
Okay, if i want to answer this question, we have to talk about the hardywebler equilibrium.
00:03
It says, well, remember that according to herdewebber, p plus q is going to be 1, where p is the frequency of alleles in the population that are dominant, q is the frequency of alils in the population that are recessive, okay? and also p square plus 2pq plus q is equal to 1, where p square is the frequency of individuals in this population that are homosego dominant, 2 pq is the frequency of individuals in each square, population that are heteroseogogos and qsquare is the frequency of individuals in this population that are homozygon excessive.
00:36
So this question said, in a population of lizards that is in hard -de -webemar equilibrium, 4 % exhibit the aggressive phenotype for color pattern.
00:44
So let's suppose that this is the allele, the dominant alleleon is the recessive allele.
00:48
So it says that 4 % exhibit the recessive phenotype for color pattern.
00:53
So practically, the homo -sigo -recessive is going to be 4%.
00:57
So, as the homo -ooseousalal.
01:00
I go to says if is q square, then it means that q square is 4%.
01:04
And 4 % is the same as 4 divided by 100...