3. $\int \frac{3x+2}{x^2+4x+5} dx$ (Hint: $\int \frac{3x+2}{x^2+4x+5} dx = \int \frac{3x+2}{(x+2)^2+1} dx$. Let $u = x+2$, and use integral formulas.)
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Then $du = dx$ and $x = u-2$. Substitute into the integral: $\int \frac{3x+2}{(x+2)^2+1} dx = \int \frac{3(u-2)+2}{u^2+1} du = \int \frac{3u-4}{u^2+1} du$ Show more…
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