Question

300 kN/m 100 kN/m A B L Replace the distributed load shown by one equivalent concentrated load. The length of the beam is L = 1.2 m. (a) What is the Magnitude of this equivalent load? Call its 3 SigFigs aaa. (b) Find its location as the distance from point A. Call its 3 SigFigs bbb.

          300 kN/m
100 kN/m
A
B
L
Replace the distributed load shown by one equivalent concentrated load. The length of the beam is L = 1.2 m.
(a) What is the Magnitude of this equivalent load? Call its 3 SigFigs aaa.
(b) Find its location as the distance from point A. Call its 3 SigFigs bbb.

300 kN/m
100 kN/m
A
B
L
Replace the distributed load shown by one equivalent concentrated load. The length of the beam is L = 1.2 m.
(a) What is the Magnitude of this equivalent load? Call its 3 SigFigs aaa.
(b) Find its location as the distance from point A. Call its 3 SigFigs bbb.

Added by James F.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ishana K

Step 1

We can do this by finding the area under the distributed load curve. Since the distributed load is a triangle, we can use the formula for the area of a triangle: Area = (1/2) * base * height The base of the triangle is the length of the beam, L = 1.2 m. The Show more…

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Replace the distributed load shown by one equivalent concentrated load: The length of the beam is L = 1.2 m. (a) What is the magnitude of this equivalent load? Call its 3 SigFigs aaa. (b) Find its location as the distance from point A: Call its 3 SigFigs bbb.