00:01
So according to this problem, there are three point churches located at the position indicated by this sketch here.
00:09
Q1 is at the origin and q2 along the y axis and q3 along the horizontal x axis.
00:18
And q1 has charged 2 times 10 to the minus 9.
00:24
Q2 has a charge of minus 4 times 10 to the minus 9 columns and q2.
00:32
Has charged minus 5 times 10 to the minus 9 columns.
00:36
So we need to calculate the resulting electrostatic force on qv specifically.
00:41
Okay, let's begin with the solution of this problem.
00:45
Let's firstly write down the formulas that we need.
00:49
What is the formula for the electrostatic force on a charged object? in our case, on a charged point particle.
01:00
So, electrostatic force equals the charge of the point particle times the electric field at the position of the particle.
01:13
Okay.
01:14
And what if, it is the case that the electric field, the position is generated by another point particle, by another point charge.
01:30
In this case, the electric field will be, the vector of electric field will be 1 over 4 pi times subsalternate times the charge of this particle that generates the electric field, q little, in distinction of what the q capital there, divided by r squared r -hat.
01:51
Okay, r -squared and r -hat.
01:53
What are this? just a reminder, this r -1 -4.
01:58
Is the relative position vector.
02:05
Okay, it is defined as the vector is the vector starting from the charge that generates the electric field up to the observation point where we, the point of interest, where we went to calculate the electric field.
02:26
Okay, this is the relative position vector.
02:29
Again, always starting from a charge, goes to the observation point...