Question

(4) 2[-x - y]^2 + 3(y - x) (a) x = 0, y = -3 (b) x = -1, y = -2 (c) x = 4, y = -1 (5) (3x + y) / (4xy) (a) x = 0, y = -3 (b) x = -1, y = -2 (c) x = 4, y = -1 (6) a^3 - 3a^2b + 3ab^2 - b^3 (a) a = 2, b = 3 (b) a = 0, b = -2 (c) a = -1, b = -3 (7) (a - b)^3 (a) a = 2, b = 3

          (4) 2[-x - y]^2 + 3(y - x)
(a) x = 0, y = -3
(b) x = -1, y = -2
(c) x = 4, y = -1
(5) (3x + y) / (4xy)
(a) x = 0, y = -3
(b) x = -1, y = -2
(c) x = 4, y = -1
(6) a^3 - 3a^2b + 3ab^2 - b^3
(a) a = 2, b = 3
(b) a = 0, b = -2
(c) a = -1, b = -3
(7) (a - b)^3
(a) a = 2, b = 3

(4) 2[-x - y]^2 + 3(y - x)
(a) x = 0, y = -3
(b) x = -1, y = -2
(c) x = 4, y = -1
(5) (3x + y) / (4xy)
(a) x = 0, y = -3
(b) x = -1, y = -2
(c) x = 4, y = -1
(6) a^3 - 3a^2b + 3ab^2 - b^3
(a) a = 2, b = 3
(b) a = 0, b = -2
(c) a = -1, b = -3
(7) (a - b)^3
(a) a = 2, b = 3

Added by Sara K.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sutara K

Step 1

For the first equation, we have: (4-1-vP + 36v-z) (0) I =0 Since the first factor is zero, the whole expression is zero, regardless of the value of I. Therefore, this equation does not provide any information about I. Show more…

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(4) 2[-x - y]^2 + 3(y - x) (a) x = 0, y = -3 (b) x = -1, y = -2 (c) x = 4, y = -1 (5) (3x + y) / 4xy (a) x = 0, y = -3 (b) x = -1, y = -2 (c) x = 4, y = -1 (6) a^3 - 3a^2b + 3ab^2 - b^3 (a) a = 2, b = 3 (b) a = 0, b = -2 (c) a = -1, b = -3 (7) (a - b)^3 (a) a = 2, b = 3