(4 pts) \begin{bmatrix} -1 & -3 & 3\\ 3 & 8 & -10\\ 2 & 6 & -8 \end{bmatrix} Then \(A^{-1} = \begin{bmatrix} \\\\\\ \end{bmatrix} \begin{bmatrix} -29\\ 78\\ 62 \end{bmatrix} Use \(A^{-1}\) to write \(b = \begin{bmatrix} \\\\\\ \end{bmatrix}\) as a linear combination of the columns of A. \(b = \begin{bmatrix} -1\\ 3\\ 2 \end{bmatrix} + \begin{bmatrix} -3\\ 8\\ 6 \end{bmatrix} + \begin{bmatrix} 3\\ -10\\ -8 \end{bmatrix}
Added by Jennifer L.
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We are given that A = 26-8, so we can write it as: A = [1 3] [3 8] Show more…
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