00:01
In the asked question, the life span of the ever run batteries used in an application is normally distributed with the mean of 3 .5 years and standard deviation of 0 .4 year.
00:12
If we denoted the life span to bx, the life span of the batteries to bx, then x year follows a normal distribution with mu equals 3 .5 years and sigma equals 0 .4.
00:29
The manufacturer decides to replace any battery that dies before the guarantee period and wants to set that lens so that no more than 5 % of the batteries will have to be replaced.
00:44
For a normal distribution like that, we want to get the value so that only 5 % of the batteries will have to be replaced.
01:01
This means we want a value here we can call it a.
01:06
That the area before it is just only 5%.
01:13
This is going to be the length set by the manufacturer.
01:19
If the battery dies before it, it will be replaced.
01:26
Before it means to have any life battery here.
01:34
Then these are going to be replaced...