(4.1) Show, using the $\epsilon - N$ method, that the sequence $a_n = \frac{3n^3 + 2}{n^3}$ converges. First determine the limit.
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The sequence is given by $a_n = \frac{3n^3 + 2}{n^3}$. To find the limit as $n \to \infty$, we can divide both the numerator and the denominator by the highest power of $n$ in the denominator, which is $n^3$. $L = \lim_{n \to \infty} a_n = \lim_{n \to \infty} Show more…
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