5. A galvanometer has a coil resistance of 20 ohm. A current of 200 microamperes deflects the needle through 10 divisions of full scale. What resistance is needed to convert the galvanometer to a full scale 10-volt meter?
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The problem states that a current of 200 microamperes (µA) deflects the needle through 10 divisions, which is the full scale. Therefore, the full-scale current, \( I_g \), is 200 µA or \( 200 \times 10^{-6} \) A. Show more…
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A galvanometer has a coil resistance of $20 \Omega$. A current of $200 \mu$ A deflects the needle through ten divisions at full scale. What resistance is needed to convert the galvanometer to a full-scale $10-\mathrm{V}$ voltmeter?
The resistance of a galvanometer coil is $25.0 \Omega,$ and the current required for full-scale defiection is 500$\mu A$ . (a) Show in a diagram how to convert the galvanometer to an ammeter reading 20.0 $\mathrm{mA}$ full scale, and compute the shumt resistance. (b) Show how to convert the galvanometer to a voltmeter reading 500 $\mathrm{mV}$
The resistance of a galvanometer coil is 25.0 $\Omega$, and the current required for full-scale deflection is 500 $\mu$A. (a) Show in a diagram how to convert the galvanometer to an ammeter reading 20.0 mA full scale, and compute the shunt resistance. (b) Show how to convert the galvanometer to a voltmeter reading 500 mV full scale, and compute the series resistance.
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