5.8 The power absorbed by the 4-k? resistor in Fig. 5.42 is: (a) 9 mW (c) 2 mW (b) 4 mW (d) 1 mW
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Using Ohm's law, we can calculate the current (I) flowing through the 4-kQ resistor: I = V / R I = 6 V / 4 kQ I = 1.5 mA Show more…
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