00:01
Hello students in this question given as a mass of the air is 2 kilogram and their initial volume is 0 .6 meter cube at temperature 120 degree celsius, which is equal to the 393 kelvin and the final temperature is 400 degree celsius, which is equal to 673 kelvin and the final pressure is given as 700 kilo.
00:36
Pascal now, we have to calculate the initial pressure by using the ideal gas equation, which is p1 p1 is equal to mr t1.
00:51
So p1 will be equal to the value of m is 2 into r is 0 .4615 kilojoule per kilogram kelvin of air into t1 is 393 upon v1 is 0 .6.
01:11
So after calculation this this will be 604 point 565 kilo pascal value of p1.
01:28
Now, we have to calculate the volume final volume.
01:34
So this will be equal to the m r e 2 upon p2.
01:43
So 2 into r 0 .4615 into t2 is 673 upon p2 is 700 kilo pascal.
01:54
So this is equal to the 0 .8873 meter cube.
02:08
This is also a answer of the part c of part.
02:24
Now, we have to calculate the first part of this question in this part.
02:32
We have to draw a graph between the p and v pressure and volume.
02:37
So v1 pressure is given as 0 .6 m cube and meter cube and the final pressure v2 is given as which which we have calculated above 0 .887 at this volume...