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6. A chemoorganotroph and a chemolithotroph in the same environment would NOT compete for (a) oxygen. (b) carbon. (c) nitrogen. (d) phosphorus. (e) All of the above would compete. 7. Which of the following is/are an example(s) for the attached growth biological treatment process? (a) Aerated lagoon (b) Oxidation pond (c) Trickling filter (d) All of the above (e) None of the above 8. Given the following data, determine the sludge volume index (SVI). Mixed liquor suspended solids: 4500 mg/L 30-minute settleability: 450 mL/L (a) 10 mL/g (b) 100 mL/g (c) 150 mL/g (d) 300 mL/g (e) 450 mL/g 9. Bacteria A shows the best growth in the condition that is ___. (a) very acidic (b) slightly acidic (c) neutral (d) slightly alkaline (e) very alkaline 10. Which of the following is/are INCORRECT for the BOD test? (a) Long time necessary to get results (b) Only biodegradable organic matter can be measured (c) Acclimated seed needed to get meaningful results (d) Pre-treatment like dilution may be necessary for toxic wastes and nitrifying conditions (e) None of the above 11. Find the theoretical TOC of 120 g/L glucose (C6H12O6) solution [Given molar mass of C=12, O=16, H=1]. (a) 12 g/L (b) 24 g/L (c) 48 g/L (d) 96 g/L (e) 120 g/L 12. Facultative bacteria are able to work in the (a) presence of oxygen only (b) absence of oxygen only (c) presence as well as absence of oxygen (d) presence of water (e) None of the above 13. A rapid and significant increase in filamentous organisms in the mixed liquor may be expected to (a) result in a far better effluent because of the great amount of surface area for absorption. (b) plug up the return sludge pumps because the filaments hang upon valves and gasket in the sludge line. (c) lead to much denser return sludge because the filaments would tend to strain the dispersed cells of ordinary organisms out of the effluent. (d) cause bulking of the sludge solids to the point that some solids might be swept out that results in turbid, poor quality effluent. (e) lead to a much lower F/M ratio because the filaments are so totally insoluble. 14. Given the following information, determine the weight percent of volatile components: Sample = 50 ml Crucible weight = 21.6329 g Crucible and dry solids weight = 21.6531 g Crucible and ash = 21.6380 g (a) 71.25% (b) 72.65% (c) 73.55% (d) 74.75% (e) 75.65%

          6. A chemoorganotroph and a chemolithotroph in the same environment would NOT compete for (a) oxygen. (b) carbon. (c) nitrogen. (d) phosphorus. (e) All of the above would compete.
7. Which of the following is/are an example(s) for the attached growth biological treatment process? (a) Aerated lagoon (b) Oxidation pond (c) Trickling filter (d) All of the above (e) None of the above
8. Given the following data, determine the sludge volume index (SVI). Mixed liquor suspended solids: 4500 mg/L 30-minute settleability: 450 mL/L (a) 10 mL/g (b) 100 mL/g (c) 150 mL/g (d) 300 mL/g (e) 450 mL/g
9. Bacteria A shows the best growth in the condition that is ___. (a) very acidic (b) slightly acidic (c) neutral (d) slightly alkaline (e) very alkaline
10. Which of the following is/are INCORRECT for the BOD test? (a) Long time necessary to get results (b) Only biodegradable organic matter can be measured (c) Acclimated seed needed to get meaningful results (d) Pre-treatment like dilution may be necessary for toxic wastes and nitrifying conditions (e) None of the above
11. Find the theoretical TOC of 120 g/L glucose (C6H12O6) solution [Given molar mass of C=12, O=16, H=1]. (a) 12 g/L (b) 24 g/L (c) 48 g/L (d) 96 g/L (e) 120 g/L
12. Facultative bacteria are able to work in the (a) presence of oxygen only (b) absence of oxygen only (c) presence as well as absence of oxygen (d) presence of water (e) None of the above
13. A rapid and significant increase in filamentous organisms in the mixed liquor may be expected to (a) result in a far better effluent because of the great amount of surface area for absorption. (b) plug up the return sludge pumps because the filaments hang upon valves and gasket in the sludge line. (c) lead to much denser return sludge because the filaments would tend to strain the dispersed cells of ordinary organisms out of the effluent. (d) cause bulking of the sludge solids to the point that some solids might be swept out that results in turbid, poor quality effluent. (e) lead to a much lower F/M ratio because the filaments are so totally insoluble.
14. Given the following information, determine the weight percent of volatile components: Sample = 50 ml Crucible weight = 21.6329 g Crucible and dry solids weight = 21.6531 g Crucible and ash = 21.6380 g (a) 71.25% (b) 72.65% (c) 73.55% (d) 74.75% (e) 75.65%

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