6. Compute the following integrals using Residue Theorem. \( a. \int_{|z|=2} \frac{5z - 2}{z(z - 1)} dz \) \( b. \int_C \frac{dz}{z(z - 2)^4} dz, \text{ where, } C: |z - 2| = 1. \)
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The function inside the integral is (5-2b)dz. Since there is no z term in the function, it is a constant function. Therefore, it has no poles. Show more…
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