7. The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 24.5 m/s is h = 2 + 24.5t - 4.9t^2 after t seconds. (a) Find the velocity after 2 s and after 4 s. (b) When does the projectile reach its maximum height? (c) What is the maximum height? (d) When does it hit the ground? (e) With what velocity does it hit the ground?
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The height (in meters) of a projectile shot vertically upward from a point $2 \mathrm{~m}$ above ground level with an initial velocity of $24.5 \mathrm{~m} / \mathrm{s}$ is $h=2+24.5 t-4.9 t^{2}$ after $t$ seconds. (a) Find the velocity after $2 \mathrm{~s}$ and after $4 \mathrm{~s}$. (b) When does the projectile reach its maximum height? (c) What is the maximum height? (d) When does it hit the ground? (e) With what velocity does it hit the ground?
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The height (in meters) of a projectile shot vertically upward from a point 2 $\mathrm{m}$ above ground level with an initial velocity of 24.5 $\mathrm{m} / \mathrm{s}$ is $h=2+24.5 t-4.9 t^{2}$ after $t$ seconds. \begin{equation} \begin{array}{l}{\text { (a) Find the velocity after } 2 \text { s and after } 4 \text { s. }} \\ {\text { (b) When does the projectile reach its maximum height? }} \\ {\text { (c) What is the maximum height? }} \\ {\text { (d) When does it hit the ground? }} \\ {\text { (e) With what velocity does it hit the ground? }}\end{array} \end{equation}
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