Question

Let $A = \begin{pmatrix} 8 & 10 \ -5 & -3 \end{pmatrix}$ and $B = \begin{pmatrix} 8 & 10 \ 5 & 4 \end{pmatrix}$. Then $AB = \begin{pmatrix} \Box & \Box \\ \Box & \Box \end{pmatrix}$

          Let $A = \begin{pmatrix} 8 & 10 \ -5 & -3 \end{pmatrix}$ and $B = \begin{pmatrix} 8 & 10 \ 5 & 4 \end{pmatrix}$.
Then
$AB = \begin{pmatrix} \Box & \Box \\ \Box & \Box \end{pmatrix}$

Let A =
< p m a t r i x > and B =
< p m a t r i x >.
Then
AB =
< p m a t r i x >

Added by Tamara R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sandip Ranjan

05/27/2022

Step 1

This gives us: -(-35 13) = -(-35) - 13 = 35 - 13 = 22 Show more…

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8 10 -(-35 13) and B=(810) 5 4 Let A = Then AB= -88

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Question

Let $A = \begin{pmatrix} 8 & 10 \ -5 & -3 \end{pmatrix}$ and $B = \begin{pmatrix} 8 & 10 \ 5 & 4 \end{pmatrix}$. Then $AB = \begin{pmatrix} \Box & \Box \\ \Box & \Box \end{pmatrix}$

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