A 3.5 kg block is pulled across a flat frictionless floor with a 2.14 N force directed 37.0 degrees above horizontal. What is the normal force acting on the block ?
Added by Kiara R.
Step 1
This can be done using the sine of the angle and the magnitude of the force. F_vertical = 2.14 N * sin(37.0 degrees) = 1.27 N Show more…
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