A \( 40 \Omega \) resistance is connected in parallel with a coil of inductance \( L \) and negligible resistance across a \( 200 \mathrm{~V}, 50 \mathrm{~Hz} \) supply and the supply current is found to be \( 8 \mathrm{~A} \). Draw a phasor diagram to scale and determine the inductance of the coil.
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First, we need to calculate the current through the resistor. Since the resistor is connected in parallel to the supply, the voltage across the resistor is the same as the supply voltage, which is 200V. Using Ohm's law (V = IR), we can find the current through the Show more…
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