00:01
We are given that it's a coil with a self -inductance of 20 henry, a resistor with a resistance of 200 oms.
00:25
So we need capacitance and a resistance in order to obtain a resonant frequency of, of 100 hertz, as well as a quality factor of 10.
00:50
So 2 pi f sub -0, which is omega -sub -0, is the square root of 1 over lc.
01:02
That's for resonant frequency.
01:06
Also, the quality factor is omega -0.
01:13
L over r, which would be the same as 2 pi f0, l over r.
01:27
All right.
01:35
I'm going to solve the first equation for c.
01:40
So 1 over l c, just squaring both sides, would give me 4 pi squared, f0 squared.
01:51
Squared and so c would be one over four pi squared f0 squared l we have values for all of these so i'm going to go to a calculator and put this into a calculator one over four times pi squared um times f0 squared f0 is 100 times l, which is 20.
02:51
That gives me 0 .127 microferrets.
03:07
Okay.
03:09
The quality factor, we know f0, we know l, and we know r, just a minute...