A coil of resistance 100 ohm and inductance 100*10^-6 H is connected in series with the 100*10^-12F capacitor . The circuit is connected to a 10V variable frequency source .The current resonant of the circuit is 0.1A and resonant frequency is 1.59*10^6 Hz.Calculate the voltage across L and C at resonance.
Added by Ashu G.
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The impedance of a series RLC circuit is given by: Z = √(R^2 + (ωL - 1/ωC)^2) where R is the resistance, L is the inductance, C is the capacitance, and ω is the angular frequency. At resonance, the impedance is purely resistive, so the imaginary part of the Show more…
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