A coil of resistance 100 ohm and inductance 100*10^-6H is connected in series with a 100*10^-12 F capacitor. The circuit is connected to a 10V variable frequency source. Calculate the resonant frequency and current resonance.
Added by Ashu G.
Step 1
The resonant frequency (f) of an LC circuit is given by the formula: f = 1 / (2π√(LC)) Given that the inductance (L) is 100*10^-6 H and the capacitance (C) is 100*10^-12 F, we can substitute these values into the formula: f = 1 / (2π√(100*10^-6 * Show more…
Show all steps
Close
Your feedback will help us improve your experience
Vipin Kumawat and 69 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A coil of resistance 100 ohm and inductance 100*10^-6 H is connected in series with the 100*10^-12F capacitor . The circuit is connected to a 10V variable frequency source .The current resonant of the circuit is 0.1A and resonant frequency is 1.59*10^6 Hz.Calculate the voltage across L and C at resonance.
Vipin K.
A 10 ohm resistor, a 90 mH coil, and a 0.015 micro F capacitor are in series across an AC source. Calculate the impedance magnitude at 1,200 Hz below the resonant frequency.
Adi S.
Sri K.
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD