A car starts traveling down a straight highway at 12:00 noon and its distance from the starting point is s(t)= 35t + 5t^3 + t^3 miles at t hours after noon A. What is the average velocity (average rate of change of position) between noon and 2 PM? B. What is the velocity of the car as a function of t ? C. When is the car going 60 miles per hour?
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Step 1: Calculate the average velocity between noon and 2 PM. Show more…
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