00:02
For the given problem, the value of diameter is given as 2 cm.
00:07
The radius of the glass is given as 30 cm.
00:15
The refractive index for the ball or the glass ball is given as 1 .50.
00:23
The distance of the object for the converging lens is given as 20 cm.
00:29
If we use the relation that refractive index of the ball, ball divided upon the object distance plus refractive index of the ear divided upon the image distance will be equals to the difference of the refractive index that is mu ear minus mu ball divided upon the radius thus on substituting the value for mu ball it is 1 .5 divided upon 20 plus mu year is 1 divided upon v will be equal to 1 more minus 1 .50 divided upon the value of r will be minus 30.
01:16
Thus, on solving, we have the value of 1 by v equals to minus of 0 .5 minus minus 30 minus 1 .5 divided upon 20.
01:30
As the value of v on solving will be equals to minus 17 .1 centimeter as it is in negative sign so it is on the left side.
01:51
Now we need to calculate the magnification.
01:55
For magnification, the value of magnification is also equals to minus of mu times ball multiplied to the image distance divided upon the reflective index of air multiplied to the object distance...