00:01
The given utility function u of x, y is equal to natural log of x, y square.
00:10
Now in part a, the given constant, let us suppose g is equal to twice of 12 times of x plus 4 times of y is equal to 108.
00:23
So we need to find value of x and y that maximize utility function u.
00:43
So consider the lagrangian function l that is u negative lambda time of g that is natural log of x, y square lambda time of 12 times of x plus 4 y negative 108.
00:59
Difference l with respect to x, then we have 1 over x square multiplied to y square negative lambda times of 12 equal to 0.
01:10
So we have y square cancel out, then we have 1 over x negative 12 times of lambda is equal to 0, equation number 1.
01:19
Difference l with respect to y, then we have 1 over x, y square multiplied to 2 x, y negative 4 times of lambda equal to 0, then we have x get cancel out, y, y get cancel out...