Question

A curve in the plane is defined parametrically by the equations $x = t^2 - 1$ and $y = 2e^t$. Find $\frac{dy}{dx}$. Choose 1 answer: A $\frac{e^t}{t}$ B $2e^t$ C $\frac{2e^t}{t}$ D $\frac{2e^t(t^2 - 1 - 2t)}{(t^2 - 1)^2}$

Name: a curve in the plane is defined parametrically by the equations x t2 1 and y 2et find fracdydx choose 1 answer a fracett b 2et c frac2ett d frac2ett2 1 2tt2 12 75257
Uploaded: 2023-06-12T21:42:53-08:00
Duration: 3 min 39 s
Channel: Zhumagali Shomanov
Description: a curve in the plane is defined parametrically by the equations x t2 1 and y 2et find fracdydx choose 1 answer a fracett b 2et c frac2ett d frac2ett2 1 2tt2 12 75257

          A curve in the plane is defined parametrically by the equations $x = t^2 - 1$
and $y = 2e^t$.
Find $\frac{dy}{dx}$.
Choose 1 answer:
A $\frac{e^t}{t}$
B $2e^t$
C $\frac{2e^t}{t}$
D $\frac{2e^t(t^2 - 1 - 2t)}{(t^2 - 1)^2}$

$a curve in the plane is defined parametrically by the equations x t2 1 and y 2et find fracdydx choose 1 answer a fracett b 2et c frac2ett d frac2ett2 1 2tt2 12 75257$

Added by Steven L.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

06/12/2023

Step 1

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A curve in the plane is defined parametrically by the equations $x = t^2 - 1$ and $y = 2e^t$. Find $\frac{dy}{dx}$. Choose 1 answer: A $\frac{e^t}{t}$ B $2e^t$ C $\frac{2e^t}{t}$ D $\frac{2e^t(t^2 - 1 - 2t)}{(t^2 - 1)^2}$